Question

11. The sum of the digits of a two digits number is 9. Also, nine times this number is thrice the number
obtained by reversing the order of the digits. Find the number.​

Answer 1

Answer:

let first number is X

second number is y

case 1

X+Y=9 multiple by 9

9x+3y=9

solving eqn 1and2.

9x +9y=81

9x+3y=9

6y=72

y=12 putting in 9x+3y=9

9x+3*12=9

9x+36=9

9x=-27

X=-3