Question

11. The value of the expression
sin? 22°+sinº 68 °
+ sinº 63º+cos 63°sin 27°
cos? 22° + cos2 68°
is
(A) 3
(B) 2
(C) 1
(D) 0​

Answer 1

Answer:

sin^2 22+sin^2 68/cos^2 22+cos^2 68+sin^2 63+sin^2 27

sin^2 22+ cos^2 22/sin^2 68+cos^2 68+sin^2 63+sin^227

=1/1+1

=2

so in this question you have two know

sinA =cos (90-A)

cosA=sin (90-A)

sin^2 A+cos^2 A=1

Step-by-step explanation:   I have followed you