Question

11. The values of two resistors are R, = (6 0.3) k12
and R2 = (10 + 0.2) k2. The percentage error in
the equivalent resistance when they are connected
in parallel is
(1) 5.125%
(2) 2%
(3) 3.875%
(4) 7%
​

Answer 1

Explanation:

I am sorry I don't no this is

Answer 2

Answer:

When the two resistors are connected in parallel, the equivalent resistance will be

R

P

=

R

1

+R

2

R

1

R

2

Differentiating both sides ,

R

P

ΔR

P

=

R

1

ΔR

1

+

R

2

ΔR

2

+

R

1

+R

2

Δ(R

1

+R

2

)

R

P

ΔR

P

=

6

0.3

+

10

0.2

+

16

0.3+0.2

=0.05+0.02+0.03125=0.10125

% error =

R

P

ΔR

P

×100=0.10125×100=10.125%

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