Question

11. The velocity-time graph of a train is shown below. From the graph, find (i) the acceleration of the train during the time interval (a) 0 to 3s (b) 3 to 53s (c) 53 to 57s (ii) the displacement of the train in first 53s.

Answer 1

Answer:

i) the acceleration of the train during

a) 0 to 3s will be (30-0)/3=10 m/s²

b) 3 to 53s will be 0 m/s² as the train moves with uniform velocity

c) 53 to 57s will be (0-30)/4=-7.5 m/s² Since it is retardation

ii) the displacement of the train in first 53 second will be (1/2×3×30)+(50×30)=1545 m

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