11. The velocity –time graph (v – t) graph, ABCD of a moving particle is shown in
the figure given below. The maximum value for acceleration is represented by the
part
(a) AB
(b) BC
(c) CD
(d) equal for all parts
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Ok let me explain you
We’ll go step by step
1st we’ll find the acceleration at A
= > v=u+at
V= 112m
U=0
T= 4sec
112= 0 + a X 4
112=4a
a= 112/4
a=28
So here the vale of acceleration is 28m/s2
We’ll go step by step
1st we’ll find the acceleration at A
= > v=u+at
V= 112m
U=0
T= 4sec
112= 0 + a X 4
112=4a
a= 112/4
a=28
So here the vale of acceleration is 28m/s2
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