Question

11. The work done in taking a charge q once round a circle of radius 'r and having a charge Q at centre is ​

Answer 1

❍ Given :

• → There is a charge = q
• → Radius of circle = r

❍ To find :

• → Work done of charge

❍ According to Question :

• → w = F.ds
• → w = FdsCosθ

☯ [ Here θ is 90° ]

• → w = FdsCos90°
• → w = Fds(0)
• → W = 0

❍ Therefore :

• → The work done in moving a charge in circle will be zero (0)

_____________________

Answer 2

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \huge \sf \pink{Given :}$

→ There is a charge = q

→ Radius of circle = r

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \large\sf \orange{To \: find :}$

→ Work done of charge

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\red☆ \green{ [ Here \: θ \: is \: 90° ]}$

→ w = FdsCos90°

→ w = Fds(0)

→ W = 0

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

$\bold{Therefore :}$

→ The work done in moving a charge in circle will be zero (0)

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

W = 0

∵ Electrostatic force is conservative force and work done by conservative force depends only upon the initial and final position. Since, final position = initial position, hence work done is zero.

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━