Question

11. There were two candidates A and B contesting for the municipal corporation election in a
town. The total number of voters in the town were 80,000. IF 90% of the voters had voted and
60% of the votes polled were cast in favour of A, find the number of votes received by B.
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Answer 1

Answer:

Votes polled = 80% of 60000

i.e 80/100*60000

=48000

Votes received by B is 100%- 60%  

=40%

therefore votes received by B is 40/100 * 48000

=19200

Step-by-step explanation:

Answer 2

Answer:

He here is your ans

Step-by-step explanation:

please mark me As Brillante