Question

11. Three parallel resistive branches are connected across a dc supply. What will be the ratio of the branch currents 1,1,:1, if the branch resistances are in the ratio R, : R:R;:: 2:4:6? (a) 3:2:6 (b) 2:4:6 (c) 6:3:2 (d) 6:2:4 (E.P.S.C. LES. EE1, 2014​

Answer 1

Answer:

i guess b 2 4 6

Explanation:

Answer 2

Answer: Ratio would be I1:I2:I3::6:4:2. Because higher the R, Lower will be the current flow through it.

Explanation: Since the connection is in parallel, so it is obvious that potential difference will be the same(=source potential difference)in all the three branches. Since we know that for a constant potential difference, current will be inversely proportional to resistance, so the current will be in ratio 6:3:2.

$l1 = \frac{1}{2} V \\ l2 = \frac{1}{4} V \\ l3 = \frac{1}{6} V$

If we simplify it by generating the LCM of all, so

$l1 =6amp \: ( 12 \div 2 = 6) \\ l2 = 3amp \: (12 \div 4 = 3) \\ l3 = 2amp \: (12 \div 6 = 2)$

Current will flow through the the branches.