Physics, asked by nidhithakur12, 1 year ago

11.
Two blocks A (1 kg) and B (3 kg) are connected by
a string passing over a smooth pulley as shown. B
rests on rough horizontal surface and A rest on B.
The co-efficient of friction between A and B is the
same as that between B and the horizontal sur-
face. The minimum horizontal force Frequired to
move A to the left is 24 N. The co-efficient of friction
is (g = 10m/s2)
1kg
B
3kg
(A) 0.67
(B) 0.5
(C)0.4
(D) 0.25​


nidhithakur12: but how to slove
varaddaithankar: I have solved it do you have any doubts
varaddaithankar: did u get it
varaddaithankar: Understood?
nidhithakur12: no i found mu = 24/70
varaddaithankar: thats right ans this is approx 0.34 but in option 0.3 is not given so .4
nidhithakur12: oh
nidhithakur12: thnks
varaddaithankar: So answer should 0.3 or 0.4 but only 0.4 is given in options
nidhithakur12: thnks

Answers

Answered by varaddaithankar
1

Explanation:

For block B

T=f1.......f(frictional force)

f1=mu×30...(1)...mu×N...mu is coefficient of friction

For A

T+f2=24.......as T will be same

f2=mu×40

from here eliminate T and coefficient can be calculated


varaddaithankar: please mark as brainliest answer
Similar questions