11. Two cells of emf 1.5 Volt and 2 Volt having respective internal resistances of 1 12 and 2 12 are connected in parallel so as to send current in same direction through an external resistance of 5 2. Find the current through the external resistance.
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Answer:
Let 1₁ and 12, be the currents flowing through the two branches as shown in the following figure. The current through the 50 resistor will be l₁ + 12 [Kirchhoff's current law].
Explanation:
(1), we get,
61₁ +5 :: 61₁ + 4.5 17 22.5 17 = 1.5 1.5
611 • 12 22.5 17 28.5 22.5 = 1.5 3 17 x 6 0.5 17 - A
17
Current through the 5 Q resistance (external resistance) =
1₁ + 12 = 0.5 4.5 + 17 17 5 -A. 17
3011 + 2512 = 7.5
and 301₁ + 4212 = 12
.(3)
....(4)
Subtracting Eq. (3) from Eq. (4), we get,
1712 = 4.5
4.5 12= A 17
Substituting this value of 12 in Eq.
(1), we get,
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