Question

11. Two complementary angles are such that twice the measure of the one
is equal to three times the measure of the other. The larger of the two
measures​

Answer 1

$\underbrace \color{aqua}\boxed{\colorbox{black}{\sf{❥αղsաҽɾ:- larger angle is 54 °}}}$

$\underbrace \color{deeppink}\boxed{\colorbox{black}{\sf{❥explanation࿐}}}$

☆ To find:-

• The measure of larger angle .

☆Given :-

• Two complementary angles are such that twice the measure of the one is equal to three times the measure of the other.

☆Formula:-

$\color{lime}\boxed{\colorbox{black}{\sf{❥sum of all complementary angles is 90° }}}$

☆Assuming:-

• Let the complementary angles be x and (90-x).

☆Solution:-

ATQ

$❥2x = 3(90 - x) \\ \\ = > 2x = 270 - 3x \\ \\ = > 2x + 3x = 270 \\ \\ = >5x = 270 \: \: \: \: \: \: \: \: \: \: \: \\ \\ = > x = \frac{270}{5} = \color{red}54°$

• Therefore, two angles are x = 54° and (90-x)=(90-54)= 36°

☆Hence:-

$\color{yellow}\boxed{\colorbox{black}{\sf{❥ two \: angles \: are \: 54° \: and \: 36° \: }}}$

$\color{violet}\boxed{\colorbox{black}{\sf{❥larger \: angle \: is \: 54°}}}$

hope it helps... :)