11)
Two dices numbers 1,2,3,4,5,6 are thrown together. The outcome faces are written as pairs.
a) How many pairs are there?
b) Make the list of pairs with sum 2,3,4,5 and 6 separately.
c) What is the probability of occuring the maximum sum ?
Answers
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1
Answer:
Favourable outcomes =36
(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)
(1,1)(2,1)(3,1)(4,1)(5,1)(6,1)
(1,1)(2,2)(3,2)(4,2)(5,2)(6,2)
(1,2)(2,2)(3,2)(4,2)(5,2)(6,2)
(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)
(1,3)(2,3)(3,3)(4,3)(5,3)(6,3)
the probability of getting each sum from 2 to 9
Sum of 2=
36
2
=
18
1
Sum of 3=
36
4
=
9
1
Sum of 4=
36
4
=
9
1
Sum of 5=
36
6
=
6
1
Sum of 6=
36
6
=
6
1
Sum of 7=
36
6
=
6
1
Sum of 8=
36
4
=
9
1
Sum of 9=
36
2
=
18
1
.
Step-by-step explanation:
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