11. Two different lengths are determined as 81.4+0.2cm and 17.2+0.3cm. Then the sum and difference
of lengths are:
A) 98.6+0.5cm and 64.2+0.5cm
B) 99.0+ 0.1cm and 64.0+ 0.1cm
C) 98.6 +0.2cm and 64.2+0.2cm 802
D) 98.6+0.6cm and 64.2+0.15cm
E) None of these
Answers
Answered by
3
Answer:
i think option e is correct
Answered by
1
Therefore the sum of lengths is 99 + 0.1 cm and the difference of lengths is 64 + 0.1 cm. ( Option B )
Given:
Two different lengths are 81.4 + 0.2cm and 17.2 + 0.3cm.
To Find:
The sum and difference of lengths.
Solution:
We can simply solve this numerical problem by using the following process.
Given 2 lengths = 81.4 + 0.2cm and 17.2 + 0.3cm.
1st length = 81.4 + 0.2 = 81.6
2nd length = 17.2 + 0.3 = 17.5
Sum of both lengths = 1st length + 2nd length = 81.6 + 17.5 = 99.1
So the sum of lengths = 99 + 0.1
Difference of both Lengths = 1st length - 2nd length = 81.6 - 17.5 = 64.1
So Difference of the lengths = 64 + 0.1
Therefore the sum of lengths is 99 + 0.1 cm and the difference of lengths is 64 + 0.1 cm.
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