Question

11. Two years ago A was twice as old as B was. If the difference in their age be 2 years, find A's age.
​

Answer 1

Answer:

1.A = 2B;

A-B =2;

Therefore B=2 and A = 4;

Present age A = 6 and B = 4;

2.present age A, B

A - B =2;

A - 2 = 2(B-2);TWO YEARS AGO

A =2 B - 2;

2B - 2 - B =2 =>B =4 & A=6;