Question

11.What is the concentration of chlorine (in mg/L) of household bleach that contains 5.25 percent by weight of Cl2? Assume the density of water = 1,000 kg/m3.​

Answer 1

Answer:

52.5x10^3 or 52500 mg/L would be the concentration of chlorine of household bleach.

Explanation:

Given, Bleach that contains 5.25% by weight of Cl2 and Density of water 1000 kg/m^3 , then =

10^3 Kg/m^3 = 10^3 x 10^3 g /10^6 cm^3 = 10^3 x 10^6 mg / 10^3 L

= 10^6 mg.L^(-1) or, 10^3 g.L^(-1)

So, concentration of chloride is -

= (5.25/100)*1000

=52.5 kg/m^3 1 kg = 1000 gm = 10^6 mg 1 m^3 = 1000 L

So, Concentration of chloride is = (52.5 x 10^6) mg/1000L Or, Concentration of chloride is = 52.5 x 10^3 mg/L = 52500 mg/L

For more information - https://zuoti.pro/qaa/1657974/2-a-what-is-the-concentration-of-chlorine-in-mgl