Question

11) What is the product of the zeroes
in 7x^2-11x+2?​

Answer 1

Answer:

Step-by-step explanation:

equation would be like this

{7x}^{2}  -  \frac{11x}{3}  -  \frac{2}{3}  

so multiply 3 in this polynomial we get

21x²-11x-2

21x²-14x+3x-2

7x(3x-2)+1(3x-2)

(7x+1)(3x-2)

so the zeroes are

x=(-1)/7 x=2/3

I hope you would like my answer.

Answer 2

Step-by-step explanation:

Quadratic polynomial is given 7x^2-11x+2

then

$\ \\ here \: \\a = 7 \\ b = - 11 \\ c = 2 \\ then \\ \\ product \: of \: its \: zeroes \\ \alpha \times \beta = \frac{c}{a } \\ then \\ \frac{c}{a } = \frac{2}{7}$

hope it helps you