11. What is the value of r in the following
network? The effective resistance of the
network between PQ is 1 12. (Ans. 22)
Answers
Correct Question :
what is the value of r in the following network. The effective resistance of the network between PQ is 1Ω
Before solving the question , Let's know about some Combination of resistors .
• Resistors in series and parallel :
1) Resistors in series :
For n resistors connected in series
the equivalent Resistance is given by
2) Resistors in parallel:
For n resistors connected in parallel
the equivalent Resistance is given by
Solution :
We have to find the vale of r
Ω
Therefore, The vale of r is 2Ω
Note :
For. step by step explanation refer to the attachment .
Answer:
Correct Question :
what is the value of r in the following network. The effective resistance of the network between PQ is 1Ω
\rule{200}2
Before solving the question , Let's know about some Combination of resistors .
• Resistors in series and parallel :
1) Resistors in series :
For n resistors connected in series
the equivalent Resistance R_{eq}R
eq
is given by
R_{eq}=R_{1}+R_{2}+R_{3}+...+R_{4}R
eq
=R
1
+R
2
+R
3
+...+R
4
2) Resistors in parallel:
For n resistors connected in parallel
the equivalent Resistance R_{eq}R
eq
is given by
\dfrac{1}{R_{eq}} = \dfrac{1}{R_{1} } + \dfrac{1}{R_{2} } + \dfrac{1}{R_{3} } + ...... \dfrac{1}{R_{n} }
R
eq
1
=
R
1
1
+
R
2
1
+
R
3
1
+......
R
n
1
Solution :
We have to find the vale of r
\sf\:R_{eq}=\dfrac{2r}{2+r}R
eq
=
2+r
2r
\implies\sf\:1=\dfrac{2r}{2+r}⟹1=
2+r
2r
\sf\implies2+r=2r⟹2+r=2r
\implies\sf\:2r-r=2⟹2r−r=2
\implies\sf\:r=2⟹r=2 Ω
Therefore, The vale of r is 2Ω
Note :
For. step by step explanation refer to the attachment .