Question

11. What number must be subtracted from each of the numbers 41,55, 36, 48, so that the differences
are proportional?
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Answer 1

Answer:

let the number to be substracted be x

so,

41-x/55-x = 36-x/48-x

or, 1968-48x-41x+x² = 1980-36x-55x+x²

or, 1968-89x = 1980 -91x

or, 91x-89x=1980-1968

or, 2x = 12

or, x =6