Question

11. What number must be subtracted from each of the numbers 41, 55, 36, 48, so that the differences
are proportional?​

Answer 1

41-x:55-x::36-x:48-x

(41-x) (48-x) =(55-x) (36-x)

1968+x²-89x=-91x+x²+1980

2x=12

x=6

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#happy math