Math, asked by sohailkhan9660pqt, 3 months ago


11. What number must be subtracted from each term of the ratio 17 : 33 so that the ratiobecomes 7 : 15?​

Answers

Answered by shifakhan6
2

Step-by-step explanation:

17:33-x:y=7:15

17-7:33-15=x:y

10:18=x:y

so the required number is 10;18

hipe you get it

Answered by bagkakali
1

Answer:

let the number is x

(17-x) : (33-x)=7 : 15

=> (17-x) /(33-x)=7/15

=> 15(17-x)=7(33-x)

=> 255-15x=231-7x

=> -15x+7x=231-255

=> -8x= -24

=> x= -24/-8= 3

=> x= 3

so 3 is subtracted

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