Question

11. Which least number should be added to 1000 so that 53 divides the sun
2. Find the largest three-digit number which is exactly divisible by 47.​

Answer 1

Answer:

11. Seven is the least number that should be added to 1000 to get 1007 which when divided by by 53, we get 19 as quotients

2.The largest or greatest 3-digit number divisible by 47 is the last number on the list above (last 3 digit number divisible by 47). As you can see, that number is 987.

Answer 2

Q.1 Given:

1000 and 53

To prove

add value=?

Solution:

In the given question if we divide the value that is 1000 by 53 it will give the value that is: 18.86

To remove this decimal value we should add some value in 1000. by hit and trial method if we add value that is 7 in 1000 it will become 1007 which is completely divisible by 53 and give the vale that is: 19.

That's why the added value is: 7  

Q.2  Largest three digit number = 999. On dividing 999 by 47, we get Quotient = 21 and Remainder = 12 So, on subtracting 12 from 999, we get 999 – 12 = 987

Hope it helps!

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