Question

11 Which term of the AP:3, 15, 27, 39, ... will be
132 more than its 54th term?​

Answer 1

Step-by-step explanation:

a= 3

d= 12

54th term = a+(n-1) d

= 3+(54-1) 12

= 3+ 53×12

= 3+ 636 = 639.

Term which is 132 more than 54th term is 771.

771 = 3 + (n-1) 12

771-3 = (n-1)×12

768/12 = n-1

64 + 1 = n

65 = n

Therefore, the term which is 132 more than 54th term will be 65th term.

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