Question

(11,y) is a point on the line joining A(3,1),B(5,4).what is y​

Answer 1

SOLUTION

GIVEN

(11,y) is a point on the line joining A(3,1) , B(5,4)

TO DETERMINE

The value of y

EVALUATION

Here the given two points are A(3,1) , B(5,4)

So the equation of the line AB is

$\displaystyle \sf{ \frac{y - 4}{x - 5} = \frac{4 - 1}{5 - 3} }$

$\displaystyle \sf{ \implies \: \frac{y - 4}{x - 5} = \frac{3}{2} }$

$\displaystyle \sf{ \implies \: 3x - 15 = 2y - 8}$

$\displaystyle \sf{ \implies \: 3x - 2y = 7}$

Now (11,y) is a point on the line AB

$\displaystyle \sf{ \implies \: (3 \times 11) - 2y = 7}$

$\displaystyle \sf{ \implies \: 33 - 2y = 7}$

$\displaystyle \sf{ \implies \: 2y =26}$

$\displaystyle \sf{ \implies \: y = 13}$

FINAL ANSWER

Hence the required value of y = 13

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Answer 2

Answer:

thanks for your question