Question

110a square-16
How i can solved this using identities​

Answer 1

Step-by-step explanation:

You, want to factorize this equation :

$110a^2 - 16$

is equal to,

$(a\sqrt{110}) ^2 - (4)^2$  (∴ 4² = 16 )

Which resembles the identity x² - y² = (x + y)(x - y)

when x = a√110 & y = 4

∴ $110 a^2 - 16 = (a\sqrt{110} + 4) (a\sqrt{110} - 4)$

The identity to be used is [∴ x² - y² = (x + y)(x - y) ] in this problem.

Answer 2

$\underline{\huge\mathfrak{Question:}}$

Factorise :

$110 {a}^{2} - 16$

$\underline{\huge\mathfrak{Answer:}}$

Step-by-step explanation:

$110 {a}^{2} - 16$

is equal to,

$(a\sqrt{110}) ^2 - (4)^2$


(∴ 4² = 16 )

Which resembles the identity x² - y² = (x + y)(x - y)

when x = a√110 & y = 4

∴ $110 a^2 - 16 = (a\sqrt{110} + 4) (a\sqrt{110} - 4)$

The identity which is used in this problem [∴ x² - y² = (x + y)(x - y) ].