Question

111 , 113 , 125 , 161 , ? , 391

Answer 1

The given series are:

111 , 113 , 125 , 161 , ? , 391

We have to find, the value of missing number (?) is:

The pattern follow:

Previous number + ($1^{3} +1^{2}$), Previous number + ($2^{3} +2^{2}$), Previous number + ($3^{3} +3^{2}$), Previous number + ($4^{3} +4^{2}$), Previous number + ($5^{3} +5^{2}$), ....

111 + ($1^{3} +1^{2}$) = 111 + (1 + 1)

= 111 + 2 = 113

113 + ($2^{3} +2^{2}$) = 113 + (8 + 4)

= 113 + 12 = 125

125 + ($3^{3} +3^{2}$) = 125 + (27 + 9)

= 125 + 36 = 161

? = 161 + ($4^{3} +4^{2}$)

⇒ ? = 161 + (64 + 16)

⇒ ? = 161 + 80 = 241

∴ The missing number (?) = 241

Thus, the value of the "missing number (?) is 241".