111=13
115=57
121=14
512=!
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Answered by
1
the answer is 28
111=13
as 1+1+1=3 and the last digit is 1
so the 111=(last digit)(sum of digits)=(1)(3)=13
similarly
115=(last digit)(sum of digits )=(5)(1+1+5)=57 (representation not multilplication)
so 512=(last digit)(sum of digit )=(2)(5+1+2)=28
111=13
as 1+1+1=3 and the last digit is 1
so the 111=(last digit)(sum of digits)=(1)(3)=13
similarly
115=(last digit)(sum of digits )=(5)(1+1+5)=57 (representation not multilplication)
so 512=(last digit)(sum of digit )=(2)(5+1+2)=28
Answered by
2
the answer is 28 because the logic for the question is is the last digit of the no.s before equal to and the sum of digits.
hope this helps u!!!!
hope this helps u!!!!
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