Question

(111) 20 cm, 99 cm, 101 cm.
(iv) 9 cm, 11 cm, 17 cm.
10. Find the hypotenuse of a right triangle whose sides containing right angle are:
(i) 10 cm and 24 cm
(ii) 8 cm and 15 cm.
11. In the Fig. 16.37, find AC.​

Answer 1

Step-by-step explanation:

10 cm and 24 cm

by Pythagoras theorm

h2 = b2 + p2

h2 = 10^2 + 24^2

h2 = 100+ 576

h2 = 676

h2 = 26^2

h= 26 (square is cancelled )

8 cm and 15 cm

by Pythagoras theorm

h2 = b2 + p2

h2 = 8^ 2 + 15^2

h2= 64 + 225

h2 = 289

h2 = 17 ^2

h = 17 ("""")

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Answer 2

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10. (i) Given:-

side = 10 cm and 24 cm

To find the hypotenuse:-

By Phythahoras Theorum:-

=> AC² = AB²+BC²

=> AC² = 10²+24²

=> AC² = 100+576

=> AC² = 676

=> AC = √676

=> AC = 26cm (which is ur hypothenuse)

(ii) Given:-

side = 8cm and 15cm

To find the hypotenuse:-

By Phythahoras Theorum:-

=> AC² = AB²+BC²

=> AC² = 8²+15²

=> AC² = 64+225

=> AC² = 289

=> AC = √289

=> AC = 17cm