Math, asked by rajannabhupathi, 11 months ago

111+333+555+777+999=2775
You have to cross out six digits in the above five 3-digit numbers so that when they are once again added together the total will be 1111
(When a digit is crossed out consider that it is replaced by a zero)​

Answers

Answered by Anonymous
9

Answer:

I

Step-by-step explanation:

I cant answer ya but I need point to ask a question

Answered by amieliaml2006
2

Answer:

I actually have to do this but with seven digits. For six digits it goes as follows

Step-by-step explanation:

cross out a 1 from the tens and a 1 from the ones place to get 100. That gives you two digits out. Cross out the 3 from the ones place wich gives you 330 and three digits gone. Remove the 5 from the tens place, giving you a 505 and four digits gone. Remove the 7 from the hundreds place to get 77. Finally, replace the 9 in the hundreds place to get 099. It should look something like this after you're done.

100+330+505+077+099=1111

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