111 cows, 185 sheep and 296 goats are to be taken across a river. There is only one boat and the boatsman says; he will take the same number and same kind of animals in each trip. Find the largest number of animals in each trip.
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Answer:
He will take 37 of one kind in each trip
Step-by-step explanation:
We need to find the HCF to of 111, 185 and 296
By prime factorization,
111 = 3 x 37
185 = 5 x 37
296 = 2³ x 37
So the HCF is 37
So, he will take 37 animals in each trip
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