Question

1111= r. 2222= t. 3333=e. 4444=n. 5555?

Answer 1

Answer is Y

1+1+1+1=4(Four)

Last letter is R, so 1111=R

2+2+2+2=8(Eight)

Last letter is T, so 2222=T

3+3+3+3=12(Twelve)

Last letter is E, so 3333=E

In the same way

5+5+5+5=20(Twenty)

hence the answer is Y :)