Question

112, 116, 124, 131,?​

Answer 1

Answer: 136

Step-by-step explanation:

After initial term, each term is equal to the previous term plus the sum of his digits.

[Ex. 116 = 112 + (1+1+2) | 124 = 116 + (1+1+6)]

Answer 2

As per the data given in the question,

$112,116,124,131,$

We have to find the last term.

First of all, we observe the all numbers.

we can see the second term is the sum if the first term of each digit.

$1+1+2=4$

When we add $4$ in $112$, we get a second term.

$112+4=116$

the sum of each digit of the second term is

$1+1+6=8$

When we add $8$ in $116$, we get a third term.

$116+8=124$

the sum of each digit of the third term is

$1+2+4=7$

When we add $7$ in $124$ , we get a fourth term.

$124+7=131$

the sum of each digit of the fourth term is

$1+3+1=5$

When we add $5$ in $131$ , we get a fifth term.

$131+5=136$

So the answer is $136$.