Question

11² + 2² = x³

Solve it ​

Answer 1

Answer:

Hii

Step-by-step explanation:

${11}^{2} + {2}^{2} = {x}^{3} \\ \\ = > 121 + 4 = {x}^{3} \\ \\ = > 125 = {x}^{3} \\ \\ = > \sqrt[3]{125} = x \\ \\ \boxed{ \huge{ x = 5}}$

Answer 2

Step-by-step explanation:

Given:-

${x}^{3} = {11}^{2} + {2}^{2}$

To Find:-

The value of x

Solution:-

${x}^{3} = {11}^{2} + {2}^{2} \\ \\ {x}^{3} = 121 + 4 \\ \\ {x}^{3} = 125$

Cube root on both sides:-

$\sqrt[3]{{x}^{3} } = \sqrt[3]{125} \\ \\ { {(x}^{3}) }^{ \frac{1}{3} } = {(125)}^{ \frac{1}{3} } \\ \\ x = { {(5}^{3}) }^{ \frac{1}{3} } \\ \\ x = 5$

$\huge\boxed{ x = 5}$