112 cm3 of h2s(g) is mixed with 120 cm3 of cl2 at STPto produced hcl has and S find the.volume of gaseous product fromed and the composition of resulting mixture
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H₂S + cl₂ ⇒2HCl + S
when 22.4L of H₂S reacts with 22.4L of cl₂ it produce 32 g sulphur
1 cm³= = 0.001L
112 cm³ of H₂S = 0.112L of H₂S
120cm³ of cl₂= 0.120L of cl₂
22.4L of H₂S produce 32 g of S
∴ 0.112 L of H₂S will produce 32/22.4 x 0.112 = 0.16g of Sulfur
when 22.4L of H₂S reacts with 22.4L of cl₂ it produce 32 g sulphur
1 cm³= = 0.001L
112 cm³ of H₂S = 0.112L of H₂S
120cm³ of cl₂= 0.120L of cl₂
22.4L of H₂S produce 32 g of S
∴ 0.112 L of H₂S will produce 32/22.4 x 0.112 = 0.16g of Sulfur
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H2S+CL2
Explanation:
10 IS THE EXPLANATION
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