Question

112. Find the magnitude and direction of the torque
acting on the square loop as shown in the
diagram where B = 1.5T along positive Z-axis,

​

Answer 1

The magnitude of torque is |τ| =  6 x 19^-4  N-m and is directed along x direction.

Explanation:

We are given:

Magnetic field B =  1.5 T

|τ| = m x B

|τ| = m.B sin θ ( i x k)

|τ| =  NIABsin θ ( i x k)

Here

• N = 1
• A = 4 x 10^-4 m^2
• B = 1.5 T
• I = 1

sin θ  = sin 90° = 1

|τ| =  NIABsin θ

|τ| = 1 x 1 x 4 x 10^-4 x 1.5 ( i x k)

|τ| =  6 x 19^-4  N-m

Thus the magnitude of torque is |τ| =  6 x 19^-4  N-m and is directed along x direction.

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