Question

112 grams of propane is combusted mention the products and write balanced chemical equation calculate how many carbondioxide molecules are there in the evolved gas in this reaction​

Answer 1

W(CO2) = 336 g

Explanation

Reaction for combustion of propane is represented as following balanced chemical question -

C3H8 + 502 -> 3CO2 + 4H2O

From this 1 mole of propane produces 3 moles of carbon dioxide.

3 x n(propane) => n(CO2)

3 x 112 / 44 => W(CO2) / 44

W(CO2) = 3 x 112 x 44 / 44

W(CO2) = 336 g

Answer 2

Answer:

W(CO2) = 336g

Explanation:

Reaction for combustion of propane is represented as following chemical equation -

C3H8 + 5O2 --》3CO2 + 4H20

From this one mole of propane produces 3 moles of carbon dioxide.

3 × n(propane) --》 n(CO2)

3 × 112/44 --》 W (CO2) / 44

W (CO2) = 3 × 112 × 44 / 44

W (CO2) = 336g

Hence, the mass of the carbon dioxide evolved in the reaction is 336g

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