Question

112. The pH of 0.5M HCl is a) log 0.5 b) log c) log 105 d) 1 -log 5​

Answer 1

pH = log 1/ [H+]

HCl is a strong acid and can be considered 100% dissociated. Therefore. The [H+] will be 0.5 molar (which can be written as 5. x 10^-1)

pH = log 1/5 x 10^-1 which equals 0.30