Question

.?
112. The solution of the differential equation
dy = (1 + y2) dx is
(a)
y = tan x + c
(b)
y = tan (x + c)
(
e)
tan-1 (y + c) = x
(a)
tan-1 (y + C) = 2x​

Answer 1

Step-by-step explanation:

साइनी स्क्वायर बटा के वन माइनस कॉस को

Answer 2

Answer:

(b) y = tan(x+c)

Step-by-step explanation:

$d {y} = (1 + {y}^{2} )dx \\ \frac{dy}{1 + {y}^{2} } = dx \\ {\tan}^{ - 1} (y) = x + c \\ y = \tan(x + c)$