11250 square tiles of side 0.2m each have been paved in a regular rectangular courtyard 25 m long..find the breadth of the courtyard
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2
Length of a tile = 0.2m
Area of 1 tile = 0.2*0.2 = 0.04m²
No. of tiles = 11250 tiles
Area of all the tiles = 11250*0.04 = 450m²
Length of the courtyard = 25m
Let the breadth of the courtyard be b
Therefore, breadth of the courtyard =
25b = 450
b = 450/25
b = 18m
So, breadth of the courtyard is 18m.
Area of 1 tile = 0.2*0.2 = 0.04m²
No. of tiles = 11250 tiles
Area of all the tiles = 11250*0.04 = 450m²
Length of the courtyard = 25m
Let the breadth of the courtyard be b
Therefore, breadth of the courtyard =
25b = 450
b = 450/25
b = 18m
So, breadth of the courtyard is 18m.
Answered by
0
Find the number tiles needed for one length:
Number of tiles = 25 ÷ 0.2 = 125
Find the number of rows:
125 tiles = 1 row
11250 tiles = 11250 ÷ 125 = 90 rows
Find the breadth:
one tile = 0.2 m
90 tiles = 0.2 x 90 = 18 m
Answer: The breadth is 18 m
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