112cm³ of water can fully occupy the container shown above. Given that the height of the vertex of the pyramid to the surface of the water is 4 cm, find the height of water.
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Base area of the given tank, A=1.0m2
Area of the hinged door, a=20cm2=20×10−4m2
Density of water, ρ1=103kg/m3
Density of acid, ρ2=1.7×103kg/m3
Height of the water column, h1=4m
Height of the acid column, h2=4m
Acceleration due to gravity, g=9.8
Pressure due to water is given as:
P1=h1ρ1g
=4×103×9.8=3.92×104Pa
Pressure due to acid is given as:
P2=h2ρ2g
=4×1.7×103×9.8=6.664×104Pa
Pressure difference between the water and acid columns:
△P=P2−P1
=6.664×104−3.92×104
=
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Answer:
triangle p = p2-p1
hope it helps you pls
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