112g of potassium reacts with 49g of sulphuric acid
Answers
Answered by
3
Explanation:
AS always, start with balanced equation : H2SO4 +2KOH yields K2SO4 +2H2O
1 mole H2SO4 reacts with 2 moles KOH. 49g/98g/mole H2SO4 = 0.5 moles
this will react with 1 mole of KOH (1:2 ratio) which is 56g
So 56g of KOH is left over (excess reactant)
ias daughter ujjain m.p mahakal ki nagari the
Similar questions