113. In triangle ABC, angle A = 90°.CA
and D is a point on AB produced, Prove
DC^2 - BD^2= 2AB.AD
Answers
Answered by
3
Answer:
In a triangle ABC,∠A = 90°, CA=AB and D is a point on AB produced. According to Pythagoras theorem, DC2 = AD2 + AC2 DC² - BD² = (AD2 + AC2) - (AD - AB)2= (AD2 + AC2) - (AD2 + AB2 - 2 AD . AB) = AD2 + AC2 - AD2 - AB2 + 2 AD . AB = AC2 - AB2 + 2 AD . AB= AC2 - AC2 + 2 AD . AB [Since AC = AB] = 2 AD . ABHence proved.
✌️ HOPE IT WILL HELP YOU ✌️
Similar questions