Question

113. You are selecting a cricket team of first 11 players out of 16 including 4 bowlers and 2
wicket-keepers. In how many ways you can do it so that the team contains atleast 3
bowlers and atleast 1 wicket-keeper?
(a) 2472
(b) 960
(c) 840
(d) 420​

Answer 1

Answer:

Choosing 3 bowlers out of 4: (43)

Choosing 1 wicket keeper out of 2: (21)

Choosing the remaining 4 players out of 12: (127)

Hence, total permutations=(43)(21)(127)=6336

Given solution:

Number of bowlers=4

Number of wicket keepers=2

Total required selection=(43)(21)(107)+(44)(21)(106)+(43)(22)(106)+(44)(22)(105)=2472

HOPE IT'S HELP YOU PLEASE MARK AS BRAINLIST AND FOLLOW ME

THANKS