Question

114. The radii of the internal and the external surfaces of a hollow hemispherical shell are in the ratio 3:5. If it is melted and recast into a hollow cylinder with the same radius of the internal and external surfaces as that of the hollow hemispherical shell, then the ratio of the height of the hemispherical shell to the height of the hollow cylinder is (1) 3:5 (2) 60 : 49 (3) 36 : 49 (4) 18:49​

Answer 1

Answer:

1 this. is a correct answer

Step-by-step explanation:

3:5

Answer 2

Answer:

Let r

1

and r

2

be the intenal and external base radi of spherical shell.

r

1

=3cm, and r

2

=5cm.

Base radius of a solid cylinder, r=7cm

Let the height of the cylinder =h

As per given statement:

The hollow spherical shell is melted into a solid cylinder, so

the volume of solid cylinder = volume of a spherical shell

πr

2

h =

3

4

π (r

2

3

−r

1

3

)

49h=

3

4

(125−27)

h=

3

8

cm