Question

مر

115. The average of five consecutive even
numbers A, B, C, D and E is 86. The
product of C and E is :
(A) 7740
(B) 7380
(C) 7568
(D) 7224​

Answer 1

Answer:

7740 is the answer of question

Answer 2

Answer:

Option -A is the answer

The product of C and E=7740

Step-by-step explanation:

Given:-

The average of five consecutive even

numbers A, B, C, D and E is 86.

To find:-

The product of C and E ?

Solution:-

The general form of an even number=2n

The five consecutive even numbers

=2x,2x+2,2x+4,2x+6,2x+8

Let A=2x

B=2x+2

C=2x+4

D=2x+6

E=2x+8

Sum of them=A+B+C+D+E

=>2x+2x+2+2x+4+2x+6+2x+8

=>10x+20

No. of numbers=5

Average=Sum of the numbers/No. of numbers

=>Average=(10x+20)/5

=>Average=5(2x+4)/5

=>Average=2x+4

According to the given problem,

Average of five consecutive even numbers=86

=>2x+4=86

=>2x=86-4

=>2x=82

=>x=82/2

=>x=41

2x=2(41)=82

2x+2=82+2=84

2x+4=82+4=86

2x+6=82+6=88

2x+8=82+8=90

So,A=82

B=84

C=86

D=88

E=90

Now, The product of C and E=86×90

=>CE=7740

Answer:-

The product of C and E=7740