Question

11576250.what is the smallest number that must divide each of the following number to make it a perfect cube​

Answer 1

there fore in this case we have to divide 11576250 by 2,5 = 2×5 = 10 to make it a perfect cube

Answer 2

Answer:

10

Step-by-step explanation:

A number is a perfect cube only when each factor in the prime factorisation is grouped in triples.

The number is 11576250.

The Prime Factorisation of 11576250 is

$2 \times 5 \times 5 \times 5 \times 5 \times 3 \times 3 \times 3 \times 7 \times 7 \times 7$

$= 2 \times {5}^{3} \times 5 \times {3}^{3} \times {7}^{3}$

Here, the prime factors 2 and 5 are not grouped as a triplets. Hence, we divide 11576250 by 10, so the obtained number becomes a perfect cube.

Thus,

$11576250 \div 10 = 1157625 = {105}^{3}$

Hence the smallest number by which 11576250 should be divided to make a perfect cube is 10.

To know more about Cube Root click the link below

https://brainly.in/question/24285

To know more about Prime Factorisation click the link below

https://brainly.in/question/3623251

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