Math, asked by hpkuku47, 3 months ago

116. f(x) = ax⁷+bx³+cx-5
where a, b, care constants. If them, 17) equal to
11​


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Answers

Answered by laiju62
1

−17 is the answer........

explanation:

Consider the given function.

f(x)=ax

7

+bx

3

+cx−5

Since, f(−7)=7

So,

f(−7)=a(−7)

7

+b(−7)

3

+c(−7)−5=7

−7

7

a−7

3

b−7c−5=7

−(7

7

a+7

3

b+7c+5)=7

7

7

a+7

3

b+7c+5=−7

7

7

a+7

3

b+7c=−12 ............(1)

Put x=7

f(7)=a(7)

7

+b(7)

3

+c(7)−5

f(7)=7

7

a+7

3

b+7c−5

f(7)=−12−5 from equation (1)

f(7)=−17

Hence, this is the answer.


hpkuku47: but how
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