Question

116. In A ABC, ZC = 90°, AB = 20 and
BC = 12. D is a point in side AC such that
CD = 9. Taking angle BDC = x, find :
(i) sin ZABC
(ii) tan x - cos x + 3 sin x.​

Answer 1

Answer:

We could compare the areas of the two small triangles and that of the larger one.

Area (ACD) + Area (DCB) = Area (ABC)

1/2*AC*CD*sin(ACD) + 1/2*CD*BC*sin(BCD) = 1/2*12*5

(Since BCD= 30 degree, hence ACD= 60 degree)

Solving for CD, we will get CD= 120/(12*3^(1/2) +5)

Answer 2

Answer:

plz mark as brainlist answer...