116.
Present age of father is 28 years
more than his son's age. Father's
age becomes 2 times of his son's
age after 20 years. Then what is
the present age of the father ?
1) 36 years
2)
38 years
3)
8 years
4)
28 years
Answers
Answer: Option A)
Steps:
Let the present age of son be 'x' years. Hence the present age of father according to the question is:
- Age of father (present) = ( x + 28 ) years
Also, it is given that father's age would become 2 times of his son's age after 20 years.
- ⇒ Father's age + 20 years = 2 ( x + 20 )
Substituting Father's age from previous equation in the latest equation we get:
→ ( x + 28 + 20 ) = 2 ( x + 20 )
→ ( x + 48 ) = 2x + 40
→ 2x - x = 48 - 40
→ x = 8 years
Hence the present age of Son is 8 years.
Hence the present age of father is:
→ 8 + 28 = 36 years
Hence the present age of the father is 36 years.
Hence Option A) is the correct answer.
Answer:
Given :-
- Present age of father is 28 years more than his son's age.
- Father's age becomes 2 times of his son's age after 20 years.
To Find :-
- What is the present age of the father.
Solution :-
» Let, the present age of son be x
» And, the present age of father will be x + 28
➙ After 20 years,
» Then, the age of son is x + 20
» And, the age of his father's will be 2(x + 20)
According to the question,
⇒ (x + 28) + 20 = 2(x + 20)
⇒ x + 28 + 20 = 2x + 40
⇒ x + 48 = 2x + 40
⇒ x - 2x = 40 - 48
⇒ - x = - 8
➠ x = 8
Hence, the required age of his son and his father will be,
✦ Age of son = x = 20 years
✦ Age of his father = x + 28 = 8 + 28 = 36 years
∴ The age of father is 36 years .
Hence, the correct options is option no (1) 36 years .
Let's Verify :-
⇒ (x + 28) + 20 = 2(x + 20)
Put the value of x = 8 we get,
⇒ (8 + 28) + 20 = 2(8 + 20)
⇒ 8 + 28 + 20 = 16 + 40
⇒ 56 = 56
➥ LHS = RHS
Hence, Verified ✔