Question

117. Two fly wheels A and B are mounted side by side with
frictionless bearings on a common shaft. Their moments
of inertia about the shaft are 5.0 kg m2 and 20.0 kg m2
respectively. Wheel A is made to rotate at 10 revolution
per second. Wheel B, initially stationary, is now coupled
to A with the help of a clutch. The rotation speed of the
wheels will become
(b) 0.5 rps
(d) 1 rps
(a) 215 rps
(c) 2 rps​

Answer 1

Answer:

hi I am studying aeronautical engineering

your answer is (c) 2 rps

Answer 2

Explanation:

When wheel B, initially stationary is coupled to A with the help of a clutch, both will have a common angular velocity and let that be ω.

Since there is no external torque, angular momentum will be conserved. From conservation of angular momentum, Iω=I

1

ω

1

+I

2

ω

2

=5×10+20×0=50

∴(5+20)×ω=50

∴ω=2rps