Math, asked by sunidhi14, 1 year ago

118-(121/(11*11)-(-4)-(3-(9-2)))

Answers

Answered by vinod04jangid
2

Answer:

118-(121/(11*11)-(-4)-(3-(9-2)))=109

Step-by-step explanation:

Given: 118-(121/(11*11)-(-4)-(3-(9-2)))

To simplify.

For this we use BODMAS rule which gives the order for what we need solve first if multiple operations are there in the expression.

BODMAS stands for Brackets, Orders, Division, Multiplication, Addition and Subtraction.

118-(121/(11*11)-(-4)-(3-(9-2)))=118-(\frac{121}{121}+4-(3-7) )

                                                                    =118-(\frac{121}{121}+4+4 )\\=118-(1+4+4)\\=118-9\\=109

Therefore, 118-(121/(11*11)-(-4)-(3-(9-2)))=109.

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Answered by yogeshkumar49685
2

Concept:

The BODMAS rule is an acronym that is used to remember the order of operations to apply while solving mathematical problems. B stands for brackets, O means for order of powers or roots, D stands for division, M stands for multiplication, A stands for addition, and S stands for subtraction. It signifies that expressions with numerous operators must be simplified in this order only, from left to right.

Given:

118-(121/(11*11)-(-4)-(3-(9-2)))

Find:

Simplifying the given expression using BODMAS

Solution:

On applying the BODMAS rule,

118-[121/(11*11)-(-4)-(3-(9-2))]

= 118-[121/(11*11)-(-4)-(3-7)]

= 118-[121/(11*11)-(-4)+4]

= 118-[121/(11*11)+4+4]

= 118-[121/121+4+4]

= 118-[1+4+4]

= 118-[9]

= 118-9

= 109

                                                                                                   #SPJ2

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